(4m^2+12m+19)/(2m-3)=

Solution for (4m^2+12m+19)/(2m-3)= equation:

(4m^2+12m+19)/(2m-3)=

We move all terms to the left:

(4m^2+12m+19)/(2m-3)-()=0


Domain of the equation: (2m-3)!=0

We move all terms containing m to the left, all other terms to the right

2m!=3

m!=3/2

m!=1+1/2

m∈R


We add all the numbers together, and all the variables

(4m^2+12m+19)/(2m-3)=0

We multiply all the terms by the denominator


(4m^2+12m+19)=0

We get rid of parentheses

4m^2+12m+19=0

a = 4; b = 12; c = +19;
Δ = b2-4ac
Δ = 122-4·4·19
Δ = -160
Delta is less than zero, so there is no solution for the equation